Question

the digit at ones place of two digit number is 4 times the digit at 10 place the number obtained by reversing the digit exceeds the given number by 54 find the given number​

Answer 1

Answer:

let the tens place digit be y then digit at ones place be 4y.

now the digit is 10y +4y = 14y.

reverse of the number is 40y + y = 41y

given 41y = 14y + 54

27y = 54.

y = 2.

and the number is 28

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