The digit at ten s place of 2-digit no is 3 times of that in one s place . If the digit are reversed the be no will be 36 less than the original number.find the no
khushi6869:
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Let the number at first digit be x.
:.Tens place=10(3x)=30x
:. Original number=30x+x=31x
ATQ-
Ones digit=3x
:.Tens digit=10x
:. New number=10x+3x=13x
ATQ-
New number-Original number=36
:.31x-13x=36
18x=36
X=36/18
X=2
:. Ones digit of number=2
& Tens digit of number=3×2=6
:. Original number=26
(ÆÑẞWĒR)
#Mærk ãß thē Bråìñlìêßt
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Tèàm Káñçhâ
:.Tens place=10(3x)=30x
:. Original number=30x+x=31x
ATQ-
Ones digit=3x
:.Tens digit=10x
:. New number=10x+3x=13x
ATQ-
New number-Original number=36
:.31x-13x=36
18x=36
X=36/18
X=2
:. Ones digit of number=2
& Tens digit of number=3×2=6
:. Original number=26
(ÆÑẞWĒR)
#Mærk ãß thē Bråìñlìêßt
Rëgārdß
Tèàm Káñçhâ
Rëgārdß
Tèàm Káñçhâ
Answered by
5
here's your answer____✔
☆according to question let, the unit digit = x then the tens digit = 3x because according to question tens digit is 3 times of unit digit.
↪let the ten's digit be x
units digit be y
x=3y
x-3y=0.....................1
10y+x=10x+y+36
9y-9x=36/9
y-x=4......................2
↪add (1) & (2)
-2y=4
y=-2
x=3y
x=-6
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hope it helps !!
☆according to question let, the unit digit = x then the tens digit = 3x because according to question tens digit is 3 times of unit digit.
↪let the ten's digit be x
units digit be y
x=3y
x-3y=0.....................1
10y+x=10x+y+36
9y-9x=36/9
y-x=4......................2
↪add (1) & (2)
-2y=4
y=-2
x=3y
x=-6
hope it helps !!
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