Question

The digit at ten's place of a 2digit no. is 3 times of the one's place of the digit at one's place is x. Answer in terms of x​

Answer 1

Answer:

Let the digit in one's place be x. the original number= 10(3x) + x (we multiplied by 10 because we have to find the value in ten's place.) so the required number is 62.

Step-by-step explanation:

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Answer 2

Answer:

3x,x

Step-by-step explanation:

let at one's place is "x" and at ten's place is "y"

so no. is "yx"

so as given

y=3x

therefore the no is 3x,x