Question

The digit at ten's place of a two digit number is four times the digit at unit's place .If the sum of this number and the number formed by reversing the digits is 55. Find the number.​

Answer 1

EXPLANATION :

Let the digit at tens place be = x

Let the digit at tens place be = x Let the digit at unit place be = y

Let the digit at tens place be = x Let the digit at unit place be = y original number = 10x + y

Reversing number = 10y + x

According to the question :-

Let the digit at one place = x

Let the digit at tens place = 4x

Original number = 10 X ( 4x ) + x = 41x

Reversing number = 10 X ( x) + 4x = 14x

If the sum of this number and the number

formed by reversing = 55

=> 41x + 14x = 55

=> 55x = 55

=> x = 1

Therefore,

Original number = 41x = 41 X 1 = 41

Done ✅

Answer 2

Answer:

1 digit ten ten place

2digit four times

55÷6=330

55×6=330

55-6 =49

55+6=61

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