Question

the digit at ten's place of a two digit number is four times the digit at ones place .if the sum of this number and the number formed by reversing the digit is 55 ,find the number

Answer 1

Solution -

Let the digit in ones place be x

So, the digit in tens place be 4x

∴ Original no. = 10(4x) + 1(x)

= 40x + x

= 41x

∴ New no. = 10(x) + 1(4x)

= 10x + 4x

= 14x    [∵By reversing the digit]

According to Question,

Original no. + New no. = 55

⇒ 41x + 14x = 55

⇒ 55x = 55

⇒ x = 55/55

⇒ x = 1

∴ Original no. = 41x = 41(1) = 41

∴ New no. = 14x = 14(1) = 14

∴ The required number is either 41 or 14

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