Math, asked by Anonymous, 1 day ago

The digit at ten's place of a two_ digit number is three times the digit at the one's place if the sum of this number and the number formed by reversing its digits is 88 find the number


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Answers

Answered by bhrsathishhema
1

Answer:

62

Explanation:

The digit at the tens place of a two digit number is three times the digit at the ones place. The sum of the number and the number formed by reversing its digits is 88. Hence, The required two digit number is 62.

Answered by rituyadav88
3

Step-by-step explanation:

The digit at the tens place of a two digit number is three times the digit at the ones place. The sum of the number and the number formed by reversing its digits is 88. Hence, The required two digit number is 62.

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