Question

the digit at ten's place of two digit number is four times the digit at one's place if the sum of this number and the number formed after reversing the digits is 55 find the number

Answer 1

A/Q
Let the digit at units place=x
then the digit at tens place=4x

Therefore the original number is=40x+x
Now,
Reverse of that no.=10x+x

Hence,
41x+11x=55
55x=55
hence, x=1

Therefore, Req. number= 41 Ans.

PLEASE MARK ME AS BRAINLIEST