the digit at ten's placeof 2 digit no. is three times of that in one's place. if the digit are reversed, the new no. will be 36 less than the original no. find no.
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Reversing the digits of a two-digit number always changes the value by a multiple of nine. Which multiple of nine? Nine multiplied by the difference in the digits. So, for example, 85 drops by 27 when you reverse the digits, because 8–5 = 3, and 3 x 9 = 27.
For your question, because the number drops by 36 on reversal of the digits, the digits must differ by 4, because 36 = 4 x 9. If the digits are a and b (with a the larger digit in the tens place), then:
a = b + 4
a = 3 * b
Subtract the first equation from the second to get
0 = 2 * b - 4,
which has the solution b = 2. Therefore a = 6, and the number is 62.
For your question, because the number drops by 36 on reversal of the digits, the digits must differ by 4, because 36 = 4 x 9. If the digits are a and b (with a the larger digit in the tens place), then:
a = b + 4
a = 3 * b
Subtract the first equation from the second to get
0 = 2 * b - 4,
which has the solution b = 2. Therefore a = 6, and the number is 62.
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