the digit at tens place is greater than digit at ones place by one.the sum of number and the number obtained by interchanging the digit is 99 . find the number
Answers
Answer:
the original no. is 54
Step-by-step explanation:
let tens place digit =x
let ones place digit=y
the original no.=10x+y(any numbers expanded form looks like this for example 23=2*10+3)
the reversed no.is =10y+x
according to the question,
10x+y+10y+x=99-------1
x=y+1------2
from equation2 we get the value of y(ones place digit)in terms of x)
which is y=x-1
now we will place it in the first equation like this,but before we do this we should simplify the equation1
10x+y+10y+x=99
10x+x+10y+y=99
11x+11y=99
11(x+y)=99
x+y=99/11
x+y=9
we will now put the value of y in this equation,
x+(x-1)=9
x+x-1=9
2x=9+1
2x=10
x=10/2
x=5
now we know the value of x so we can easily find the value of y,
in equation 2 by putting the value of x we can get the value of y
x-1=y
5-1=y
y=4
thus the original no. is 54
Answer:54
Step-by-step explanation:
I hope it's helpfull for you