The digit at tens place is twice the digit at unit place in a two digit number. The number formed by interchanging the digits is 18 less than the original number. Find the two digit number. Only one variable is allowed.
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Answer:
let the ten's digit be x and unit digit be y.
Then
ATQ,
=> x = 2y
And
=> 10x + y - 18 = 10y + x
=> 9x - 9y = 18
=> x - y = 2
=> 2y - y = 2
=> y = 2
Thus x = 4
Original Number = 42
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