Question

The digit at tens place is twice the digit at units place in a two digit number. number formed by interchanging the digit is 18 less than the original number. find the 2-digit number. (pls explain also:))

Answer 1

Answer:

ANSWER

Let 10y+x be the digit number.

It is given that the ten's place is twice the digit at unit's

place.

i.e. y=2x ------(1)

Also, (10y+x)+(10x+y)=66

10y+x+10x+y=66

11y+11x=66

⇒x+y=6

⇒x+2x=6 [from (1)]

⇒3x=6

⇒x=2

Form (1), y=2(2)=4

The required number =42

Answer 2

Step-by-step explanation:

10y+x be the digit number.

It is given that the ten's place is twice the digit at unit's

place.

i.e. y=2x ------(1)

Also, (10y+x)+(10x+y)=66

10y+x+10x+y=66

11y+11x=66

⇒x+y=6

⇒x+2x=6 [from (1)]

⇒3x=6

⇒x=2

Form (1), y=2(2)=4

The required number =10(4)+2=42