The digit at tens place is twice the digit at units place in a two-digit number.
The number formed by interchanging the digits is 18 less than the original
number. Find the two-digit number.
Answers
Answered by
15
Hey!!!
_____________
let the ten's digit be x and unit digit be y.
Then
ATQ,
=> x = 2y
And
=> 10x + y - 18 = 10y + x
=> 9x - 9y = 18
=> x - y = 2
=> 2y - y = 2
=> y = 2
Thus x = 4
Original Number = 42
_________
Hope this helps
_____________
let the ten's digit be x and unit digit be y.
Then
ATQ,
=> x = 2y
And
=> 10x + y - 18 = 10y + x
=> 9x - 9y = 18
=> x - y = 2
=> 2y - y = 2
=> y = 2
Thus x = 4
Original Number = 42
_________
Hope this helps
RishabhBansal:
welcome
can u answer one more question,
yes
One-third of the herd of cows are grazing in the field, 20 less than half of
them are near the river. The remaining 35 are tied with the trees. Find the
total number of cows in the herd.
them are near the river. The remaining 35 are tied with the trees. Find the
total number of cows in the herd.
pls help
I'm answering on your profile
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go to that question
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Answered by
0
The two-digit number is 42.
Given:
The digit at tens place is twice the digit at units place in a two-digit number. The number formed by interchanging the digits is 18 less than the original number.
To Find:
Find the two-digit number.
Solution:
Let the digit at ten's place be x and at the ones place be y.
According to what is given,
⇒x = 2y ---- eq 1
Also,
⇒10x + y -18 = 10y + x
⇒9x - 9y = 18
⇒x - y = 2 ---- eq 2
By replacing the value of x from eq 1 in eq 2
⇒2y - y = 2
⇒y = 2
Therefore, x = 2(2) = 4
The two-digit number is 42.
#SPJ2
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