Math, asked by ishank6cgmailcom, 8 months ago

the digit at tens place of a two-digit number is three times the digit at the ones place.If the sum of this number and number formed by reversing its digits is 88,find the number​

Answers

Answered by judhisthirbedasasan
1

Answer:

let the ones digit be x and tens digit be 3x

according to the question

10x+3x=88

13x=88

x=88/13

x=6.77

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