Question

the digit at tens place of a two digit number is to type the digit at ones place if the digit is reversed the number become 18 less than the original number what is the original number​

Answer 1

Answer:

Step-by-step explanation:

→ let x be the number at the unit places

→ y be the number at tens place.

two digit number=10y+x

according to conditions

y=2x

2x-y=0                   ....(1)

10x+y+10y+x=66

x+y=11                   ......(2)

solve (1)  and (2) we get

x=2     and y=4

two digit number = 10y+x=42