Question

The digit at tens place of two digit number is 3 more than the digits in the units place. Let the digit at units place be b, then the number is
a) 11b+30
b) 10b+30
c) 11b+3
d) 10b+3

Answer 1

Answer:

Refers to the attachment

Answer 2

Number is 11b + 30 if The digit in the tens place of a two digit number is 3 more than the digit in the unit place and digit at units place is b

Given:

• A two digit number
• The digit in the tens place  is 3 more than the digit in the unit place.
• Digit at unit place is b

To Find:

• Number

Solution:

Step 1:

Add 3 in b to find digit at tens place

3 + b

Step 2:

Find the number by multiplying tens digit with 10 and Adding unit digit.

10 (3 + b) + b

Step 3:

Simplify the expression:

30 + 10b + b

= 11b + 30

Number is 11b + 30 if The digit in the tens place of a two digit number is 3 more than the digit in the unit place and digit at units place is b

Correct option is a)  11b+30