The digit at tens place of two digit number is 3 more than the digits in the units place. Let the digit at units place be b, then the number is
a) 11b+30
b) 10b+30
c) 11b+3
d) 10b+3
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Number is 11b + 30 if The digit in the tens place of a two digit number is 3 more than the digit in the unit place and digit at units place is b
Given:
- A two digit number
- The digit in the tens place is 3 more than the digit in the unit place.
- Digit at unit place is b
To Find:
- Number
Solution:
Step 1:
Add 3 in b to find digit at tens place
3 + b
Step 2:
Find the number by multiplying tens digit with 10 and Adding unit digit.
10 (3 + b) + b
Step 3:
Simplify the expression:
30 + 10b + b
= 11b + 30
Number is 11b + 30 if The digit in the tens place of a two digit number is 3 more than the digit in the unit place and digit at units place is b
Correct option is a) 11b+30
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