the digit at tens place of two digit number is 4 times that in the unit place the digits are reversed the new number will be 54 less than original number find the original number
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Answered by
29
ANSWER
Let the original number be xy=10x+y
Digit's on 10′s place=x
Digit in units place=y
Given that x=4y
reversed number yx=10y+x
yx=xy−2710y+x=10x+y−279x=9y+27x=y+3x=4y4y=y+33y=3y=1x=4(1)=4
∴ original number=4
Answered by
43
☯ Let's consider the ten's digit and unit digit of original number be x and y respectively.
⠀⠀⠀⠀
Therefore,
- The two digit number is = 10x + y
⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━
- The digit at tens place of two digit number is 4 times that in the unit place.
⠀⠀⠀⠀
⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━
Also,
- If the digits are reversed the new number will be 54 less than original number.
⠀⠀⠀⠀
Number after reversing digit = 10y + x
⠀⠀⠀⠀
Therefore,
⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━
BrainIyMSDhoni:
Superb :)
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