Question

the digit at tens place of two digit number is greater than the square of digit at unit place ( x) by 5 and number formed is 61​

Answer 1

Answer:

Suppose that,

The two digit number is 10x+y

Then, the unit palace is y and tens palace is x

According to given question,

y=x

2

…… (1)

Then,

Again, according to given question,

10x+y+54=10y+x

⇒10x−x+y−10y+54=0

⇒9x−9y+54=0

⇒x−y+6=0......(2)

From equation (1) to,

⇒x−x

2

+6=0

⇒−x

2

+x+6=0

⇒x

2

−x−6=0

⇒x

2

−(3−2)x−6=0

⇒x

2

−3x+2x−6=0

⇒x(x−3)+2(x−3)=0

⇒(x−3)(x+2)=0

For,

x−3=0

x=3

Put in (2)

Then,

x−y+6=0

3−y+6=0

−y+9=0

y=9

Then,

The number is

10x+y

⇒10×3+9

⇒39

Hence, this is the answer.

Step-by-step explanation:

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