Question

the digit at the ten place of two digit number four time the digit at one place.if the sum of this number and the number formed by reversing the digit is 55​

Answer 1

Answer:

41

Step-by-step explanation:

4(10x)+x =2 digit number

4(10x)+x+(10x+4x)=55

41x+14x=55

55x=55

x=55/55

x=1

now the digit is 4(10×1)+1 = 41

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