Question

the digit at the ten's place of a two digit number is 4 times that in the unit's place. if the digits are reversed, the new number will be 54 less than the original number find the original number. check your solution

Answer 1

Let the unit digit of original no. is y and ten's digit is x

hence the two digit no.= 10x+y

now according to the question

x=4y.................(1)

if the digits are reversed the new no. become 10y+x

Hence

10y+x=10x+y-54.............................(2)

Put the value of x from 1 in 2 we get

10y+4y=40y+y-54

27y=54

y=2

Therefore x=8

Hence the original no. = 10*8+2= 82

Answer 2

Step-by-step explanation:

So guys this is the answer of your question I hope it help y