Question

The digit at the ten's place of a two digit number
is four times that in the unit's place. If the digits
are reversed, the new number will be 54 less than
the original number. Find the original number,
Check your solution.
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Answer 1

Answer:

this is your Answer hope it helps you

Step-by-step explanation:

Let the original number be xy=10x+y

Digit's on 10

′

s place=x

Digit in units place=y

Given that x=4y

reversed number yx=10y+x

yx=xy−27

10y+x=10x+y−27

9x=9y+27

x=y+3

x=4y

4y=y+3

3y=3

y=1

x=4(1)=4

∴ original number=4

Answer 2

refer the attachment ⚡

be brainly ⚡

hope this helps ☺️,