Question

the digit at the ten's place of four times the digit at ones place if the sum of this number and the number formed by reversing digit is 55 find the number

Answer 1

The number is 41 as 4 is in the tens place and is four times the digit in the ones place which is 1 and when you reverse the digits you get 14 and when you add 41 and 14 ..you get 55 . Thus 41 is the number.

Pls vote brainless!

Answer 2

let the number of the form 10x+y

given that: 4y=x -----1

and; 10x+y + 10y+x=55-----2

therefore in eqn 2

11(x+y)=55

x+y=5

from eqn 1

x+4x=5

x=1, therefore y=4

so the number is 10x+y=40+1=41