Question

the digit at the tens place of a 2 digit number is three times the digit at the ones place if the sum of thisnumber and the number formed by reversing its digit is 8i find the number

Answer 1

let x = the 10's digit
let y = the units
then
10x+y = the number
:
Write an equation for each statement:
:
" the digit at the tens place of a two digit number is three times the digit at ones place."
x = 3y
:

"The sum of this number and the number formed by reversing its digit is 88,"
(10x + y) + (10y + x) = 88
10x + x + 10y + y = 88
11x + 11y = 88
simplify, divide by 11
x + y = 8

Answer 2

LET THE NUMBER AT THE ONE'S PLACE BE x
SO... TEN'S PLACE DIGIT = 3x
3x + x = 8
4x+8
x=4/8
= 2
so one's place digit is 2 and ten's place digit is 3*2= 6
hence the two digit no. is 26