Question

the digit at the tens place of a 2-digit number is three times the digit at the ones place. if the sum of this number and the number formed by reversing its digits is 88,find the number.​

Answer 1

• let the digit in one's place be x. the original number= 10(3x) + x (we multiplied by 10 because we have to find the value in ten's place.) so the required number is 62

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