the digit at the tens place of a 2 digit number is three times the digit at the ones place if the sum of the number and the number formed by reversing the digit is 88. find the number.
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Answer:
the number is 62.
Step-by-step explanation:
Let the digit at tens place be x and the digit unis place be y.
Then the original number will be 10x+y.
The digit at tens place is three times the digit at the units place.
i.e. x=3y ....(1)
The sum of this number and the number formed by reversing its digits is 88.
(10x+y)+(10y+x)=88
⇒11x+11y=88
⇒x+y=8 ....(2)
Substitute the value of equation (1) in equation (2).
Therefore, 3y+y=8
⇒4y=8
⇒y=2
Therefore, x=3y=3×2=6
Therefore, the original number is 62.
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