Question

the digit at the tens place of a 2 digit number is three times the digit at the ones place if the sum of the number and the number formed by reversing the digit is 88. find the number.​

Answer 1

Answer:

the number is 62.

Step-by-step explanation:

Let the digit at tens place be x and the digit unis place be y.

Then the original number will be 10x+y.

The digit at tens place is three times the digit at the units place.

i.e. x=3y ....(1)

The sum of this number and the number formed by reversing its digits is 88.

(10x+y)+(10y+x)=88

⇒11x+11y=88

⇒x+y=8 ....(2)

Substitute the value of equation (1) in equation (2).

Therefore, 3y+y=8

⇒4y=8

⇒y=2

Therefore, x=3y=3×2=6

Therefore, the original number is 62.