Question

the digit at the tens place of a two digit number is 3 times the digit at unit place . if the digit are reversed the new number will 36 less than the original number​

Answer 1

Answer:

Step-by-step explanation:

let the no be

3x*10+x

And on reversing the no become

X*10+3x

Then on subtracting these two we get 36

Then

30x+x-10x-3x=36

18x=36

X=2

Then the no is 3*2*10+2= 62

I think this will help you

Please mark this as brainilist

Answer 2

Step-by-step explanation:

let the digit in unit place is=x

and the digit in tens place is=3x

so, the number is =(3x)10+x

=30x+x

=31x

in reversing the digits,

the digit in tens place is =x

and the digit in unit place is =3x

so, the new number formed is=(x)10+3x

=10x + 3x

=13x

according to the question ,

31x -36 = 13x

or, 31x - 13x = 36

or, 18x = 36

or, x = 36 ÷ 18

or, x = 2

so, the digit in unit place is = x

=2

and the digit in tens place is =3x

=3 × 2

=6

so, the number is = 26