Question

the digit at the tens place of a two digit number is four times the digit at ones place . if the sum of thus number and the number formed by reversing the digit is 55,find the number​

Answer 1

Let the digit at one's place be x.

The digit at ten's place=4x

Therefore, the two digit number=10(4x) +x=40x+x=41x

On reversing the number,the digit at one's place =x

And the digit at ten's place=4x

So, the two digit no.=10(x)+4x

=10x+4x=14x

=According to the question,

=41x+14x=55

=55x=55

=x=55/55

=x=1

The two digit number=41x=41*1=41

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