The digit at the tens place of a two digit number is four times the digit at ones place.if the digits are reversed ,the new number will be 54 less than the original number.find the original number.check your solution
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Let the Number at the units place be x.Tenth place = 4x
Then,
➳ Number = 10(x) + 4x
➳ Number = 10x + 4x
➳ Number = 14x
___________________
➳ Reversing Number = 10(4x) + x
➳ Reversing Number = 40x + x
➳ Reversing Number = 41x
According to Question now,
➳ 14x - 41x = -54
➳ -27x = -54
➳ x = -54/-27
➳ x = 54/27
➳ x = 2
Units place = x = 2
Tenths place = 4x = 4(2) = 8
Therefore,
Number = 10(8) + 2 = 80 + 2 = 82
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