Math, asked by dhshi, 1 year ago

The digit at the tens place of a two digit number is four times the digit at ones place.if the digits are reversed ,the new number will be 54 less than the original number.find the original number.check your solution

Answers

Answered by Messi71
1
This is your answer please mark it as brainliest answer
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Answered by Anonymous
2

Answer:

Let the Number at the units place be x.Tenth place = 4x

Then,

➳ Number = 10(x) + 4x

➳ Number = 10x + 4x

➳ Number = 14x

___________________

➳ Reversing Number = 10(4x) + x

➳ Reversing Number = 40x + x

➳ Reversing Number = 41x

According to Question now,

➳ 14x - 41x = -54

➳ -27x = -54

➳ x = -54/-27

➳ x = 54/27

➳ x = 2

Units place = x = 2

Tenths place = 4x = 4(2) = 8

Therefore,

Number = 10(8) + 2 = 80 + 2 = 82

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