Question

the Digit at the tens place of a two digit number is three times the digit at ones place if the sum of this number and the number formed by reversing its digit is 88 find the number​

Answer 1

Answer

let digit at ones place be x

branded digit at the tens place will be e equal to 3x

defer the number is 10+(3x)+x

30 x + x

31 x

by reversing the digit we get 10 (x)+3x

10 X + 3 x

13 x

their sum ,= 88

31 X + 13 x= 88

44x = 88

x =88/44

then the digit are x3x= and 3(2)

2 and 6

the number= 31x

=31(2)

62

the number is 62

Explanation:

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Answer 2

Answer:

the answer is 62 ... hehe xd