Question

The digit at the tens place of a two-digit number is three times the digit at once place.if the sum of this number and the number formed by reversing its digits is 88,find the number

Answer 1

Answer:

let the digit in one's place be x. the original number= 10(3x) + x (we multiplied by 10 because we have to find the value in ten's place.) so the required number is 62.