the digit at the tens place of a two digit number is three times the digit at the one place if the sum of the number and the number formed by reversing its digit is 88 find the number solve it
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let the two digit number be xy
then according to the question
y=3x
and
x+10*y+y+10*x=88
11(x+y)=88
x+y=8
using first equation 4x=8 so,x=2
and y=3*2=6
hence ur answer is 26
then according to the question
y=3x
and
x+10*y+y+10*x=88
11(x+y)=88
x+y=8
using first equation 4x=8 so,x=2
and y=3*2=6
hence ur answer is 26
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