Question

the digit at the tens place of a two digit number is three times the digit at the one place if the sum of the number and the number formed by reversing its digit is 88 find the number solve it

Answer 1

let the ones place be x
tens place is 3x
so according to statement
no is 10*3x+x=31x
reverse no 10*x+3x=13x
their sum is 88
so 31x+13x=88
44x=88
x=2
tens place is 6
so the no is 6*10+2=62

Answer 2

Answer:

62

Step-by-step explanation:

let the digit at tens place- x

digit at tens place- 3x

so number is-

10(3x)+x

=30x+x

=31x

by reversing the digit we get

=10x+3x

=13x

sum of the digit:-88

31x+13x+88

44x=88

x=2

digits are

2

3(2)= 6

the number is;-

31(x)

31(2)

64