Question

the digit at the tens place of a two digit number is three times the digit at the ones place if the sum of the number and the number formed by reversing its digit is 88 find the numbers

Answer 1

Let the digit at ten's place be y and digit at unit place be x

the digit at ten's place is three times the digit at the one's place
so y = 3x .....(1)
let the original no. be 10y + x ......(2)
and the reversed no. be 10x + y ........(3)

Adding (2) and (3)
(10y + x) + (10x + y) = 88 ....(given)
10y + y + 10x + x = 88
11y + 11x = 88
y + x = 8
(3x) + x = 8 ..... from (1)
4x = 8
x = 2
y = 3x
y = 3*2
y = 6

Putting values in (2)
we get 10(6) + (2) = 60 + 2 = 62.

hope this helps :)