the digit at the tens place of the two digit number is four times that in the units place if the digit is reversed the number will be for 54 less than the original number find the original number
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let the digits be x and y
therefore
x=4y.
And
10x+y is the original number
reversed number is 10y+x
therefore
10x+y - (10y+x) =54
10*4y +y - 10y +4y =54
40y+y-4y-10y=54
27y=54
y=2
therefore
x=4*2=8
therefore original number
8*10 + 2
82
therefore
x=4y.
And
10x+y is the original number
reversed number is 10y+x
therefore
10x+y - (10y+x) =54
10*4y +y - 10y +4y =54
40y+y-4y-10y=54
27y=54
y=2
therefore
x=4*2=8
therefore original number
8*10 + 2
82
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