Question

The digit at the tens place of the two digit number is three times the digit at the unit place if the digit are reserved the number will be 36 than the original number find the number

Answer 1

let the ones place no. be x 

and tens place no. be 3x

therefore the original no be = 10 × 3x + x = 30x + x

on reversing the no.

the new no. be 10 × x + 3x = 10x + 3x

ATQ

30x + x - (10x + 3x) = 36

31x - 10x - 3x + 36

18x = 36

x = 2

so, the original no. is 10×3×2+2=62

Answer 2

According to question , we have to let a 2-digit no. as shown....

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