Question

the digit at the tens place of two digit number is 3 times the digit at the units place if the digits are reversed the new number will be 36 less then the exiginal number find the number​

Answer 1

Answer:

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i)

Reversed number = 10y + x

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4 x=3y ∴x=6

y=2

∴ Number = 62

Answer 2

Answer:

let the one's digit be y and tens digit be x number =10x+y then,x =3y (i) Reversed number =10y +xA. t .Q:- (10x + y) - (10y + x ) = 36 put x