Question

the digit at the tens place of two digit number is 4 times the digit at ones place if the sums of these numbers and the number formed by reversing the digit is 55 find the number​

Answer 1

let the no. be 10x + y

A/Q,

=> x = 4y

=> x - 4y = 0 ...................eq.1

and

=> 10x + y + 10y + x = 55

=> 11x + 11y = 55

=> x + y = 5 .............eq.2

solving equation 1 and 2 we get

x - 4y = 0

x + y = 5

__________

-5y = -5

y. = 1

using eq.1 we get

=> x = 4y

=> x = 4

the required no. = 4x10 + 1

= 41