The digit in a number at tens place is 5 less than twice the digit at units place. The sum of the original number and the number obtained by interchanging the digits is 176. Then find the two digit number.
Answers
Answered by
3
Answer:
let the digit at tens place be x and units place be y
so the original number is 10x+y
2y-5=x
2y-x=5 [1]
and also
10x+y+10y+x=176
by solving this we get
x+y=16[2]
by adding 1 and 2 we get
3y =21
so y=7
by puting value of y in 2 we get
x=9
so the number be 9*10+7=97
answer is - 97
Step-by-step explanation:
Similar questions