Question

The digit in a number at tens place is 5 less than twice the digit at units place. The sum of the original number and the number obtained by interchanging the digits is 176. Then find the two digit number.

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Answer 1

Answer:

let the digit at tens place be x and units place be y

so the original number is 10x+y

2y-5=x

2y-x=5 [1]

and also

10x+y+10y+x=176

by solving this we get

x+y=16[2]

by adding 1 and 2 we get

3y =21

so y=7

by puting value of y in 2 we get

x=9

so the number be 9*10+7=97

answer is - 97

Step-by-step explanation: