The digit in ten's place of a two digit no. Is three times of that in unit place .if the digit is reversed , then the no.will be 36 less than the original no. .find the original no..
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Let us assume, x is the tenth place digit and y is the unit place digit of the two-digit number.
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x = 3y --------------1
Also given:
10y + x = 10x + y - 36
9x - 9y = 36
x - y = 4 -------------2
Substitute the value of x from equation 1 in equation 2
3y - y = 4
2y = 4
y = 2
Therefore, x = 3y = 3 * 2 = 6
The original two-digit number is 10x + y = 10*6 + 2 = 62
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x = 3y --------------1
Also given:
10y + x = 10x + y - 36
9x - 9y = 36
x - y = 4 -------------2
Substitute the value of x from equation 1 in equation 2
3y - y = 4
2y = 4
y = 2
Therefore, x = 3y = 3 * 2 = 6
The original two-digit number is 10x + y = 10*6 + 2 = 62
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