the digit in ten's place of a two- digit number is 3 more than the digit in the unit's place. let the digit at the unit's place be b. if sum both the digits be 9. then find the number
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63
Step-by-step explanation:
Unit digit is 3
The digit in ten's place is 3 + 3 = 6
Sum of 3 and 6 is 9
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