Question

the digit in tens place of a 2 digit number is twice that of the unit digit.if the digit are reversed,the new number is 18 less than the original number.Find the number​

Answer 1

Answer:

Let the digit at ten's place and unit place be (2x) and x.

Original number 10(2x)+x=21x

Reversed number=10(x)+2x=12x

A/q. 21x-12x=18

9x=18

x=2

Required number=21(2)=42.

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Answer 2

Answer:

42

Step-by-step explanation:

Let the number be 10x+y

we know that x=2y

so the number is =10(2y)+y = 21y

reversed number = 10y+x = 10y+2y = 12y

given: 21y-12y=18

           9y=18

              y=2    x=4

Number = 42