Question

the digit in tens place of a two digit number is 4 times the digit in one's place. if u interchange the digit of this two number and add the resulting number to the original number, u get 55. what is the original number​

Answer 1

✽ Question ✽

The digit in tens place of a two digit number is 4 times the digit in one's place. If you interchange the digit of this two number and add the resulting number to the original number, you get 55. What is the original number?

✽ Given ✽

• The digit in tens place of a two digit number is 4 times the digit in one's place.
• If you interchange the digit of this two number and add the resulting number to the original number, you get 55.

✽ To find ✽

The original number.

✽ Solution ✽

Let the ones digit be x.

So, tens digit = 4x.

According to condition,

{10(4x)+x} + {10x+4x} = 55

→ 40x+x+10x+4x = 55

→ 55x = 55

→ x = 55/55

→ x = 1

✽ Hence ✽

x = 1

Ones digit = x = 1

Tens digit = 4x = (4×1) = 4

So, original number

= (10×4)+1

= 40+1

= 41

✽ Therefore ✽

The original number is 41.

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✽ Verification ✽

Original number = 41.

Number with interchange digits = 14.

So,

{10(4x)+x} + {10x+4x} = 55

→ 41 + 14 = 55

→ 55 = 55

So, L.H.S = R.H.S.

Hence, verified.

◎ Hope this helps you. ◎