the digit in tens place of a two digit number is twice the digit numbers ones place. if you interchange the digits of the two numbers the new number is 18 less than the orginal number !!!!
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Answer:
Step-by-step explanation:
Let the number at units place be x
Digit at tens place be 2x
The number=10(2x)+1(x)
After interchanging places
Number=10(x)+1(2x)
According to conditions
(10(2x)+1(x))-(10(x)+1(2x))=18
(20x+x)-(10x+2x)=18
21x-12x=18
9x=18
x=18/9
x=2
Therefore original number=10(2x)+1(x)
=10×4+2
=40+2
42
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please, mark as the brainliest ^_^
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