the digit in tens place of two digit number is three time that in one's place if the digit are reversed the new number will be 36 less than the original number find the original number
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it is given that the original no is only reversed so if reversed no. is 36 then original no is (63)....
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x=tens place
y=ones place
original number=xy =10x +y
reversed number=yx =10y+x
x=3y ....(1)
(10y + x)-36= 10x +y ......(2)
By calculating we we get,
x=6
y=2
original number is 62
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