Question

The digit in tens place of two digit number is three times than that in the units place. If the digits are reversed the new number will be 36 less than the original number. Find the original number.

Answer 1

Answer:

the required number is 62

Answer 2

Answer:

62

Step-by-step explanation:

Let say ‘x' is digit on one's place so 3x is digit on tens' place

So number is 10*3x+x=31x

Now if reverse the position of digit new number is

10*x+3x=13x

As given new number is less by 36 from old number

31x-36=13x

18x=36

x=2

So number is 10*3*2+2=62.

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