Question

The digit in tens place of two-digit number is three times than that in the units place. If the digits are reversed, the new number will be 36 less than the original number. Find the original number.

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Answer 1

Answer:

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i) 

Reversed number = 10y + x 

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4  x=3y  ∴x=6

y=2

∴ Number = 62

Step-by-step explanation:

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