Question

the digit in tens place of two digit number is twice the digit number ones place if you interchange the digits of two digit number the new number is 18 less than the original number find the original number ​

Answer 1

Let ten's digit be x

And one's digit be y

A.T.Q,

x=2y -(1)

(10x+y)-(10y+x)=18

10x+y-10y-x=18

9x-9y=18

x-y=2

from eq (1)

2y-y=2

y=2

from (1):

x=4

thus,

required number is 42

Answer 2

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