Question

The digit in the ones place of a 2-digit number is twice the digit at the tens
place. Write the number.
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Answer 1

Let ten's digit be "M" and one's digit be "N".The digit at ten's is 2 more than twice the digit in once.According to question, => M = 2 + 2N ____ (eq 1)The number formed by reversing the order is five more than three times the sum of digits.Original number = 10M + NRevered number = 10N + M According to question, => 10N + M = 5 + 3(M + N)=> 10N + M = 5 + 3M + 3N=> 10N - 3N + M - 3M = 5=> 7N - 2M = 5=> 7N - 2(2 + 2N) = 5 [From (eq 1)]=> 7N - 4 - 4N = 5=> 3N = 5 + 3=> 3N = 9=> N = 3Put value of N in (eq 1)=> M = 2 + 2(3)=> M = 2 + 6=> M = 8So,Original number = 10M + N=> 10(8) + 3=> 83∴ Original number is 83.

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