The digit in the ones place of a two digit number is three times the digit in the tens place. If the digits are interchanged, then new two digit number is 10 more than twice the original two digit number. What is the original number?
Answers
Answered by
4
Step-by-step explanation:
let the ones place no. be x
and tens place no. be 3x
therefore the original no be = 10×3x+x=30x+x
on reversing the no.
the new no. be 10×x+3x=10x+3x
ATQ
30x+x-(10x+3x)=36
31x-10x-3x+36
18x=36
x=2
so, the original no. is 10×3×2+2=62
Answered by
2
let the ones place no. be x
and tens place no. be 3x
therefore the original no be = 10×3x+x=30x+x
on reversing the no.
the new no. be 10×x+3x=10x+3x
ATQ
30x+x-(10x+3x)=36
31x-10x-3x+36
18x=36
x=2
so, the original no. is 10×3×2+2=62
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