Math, asked by Ironbanner12, 10 months ago

The digit in the ten's place of a two digit no is 3 times of that at the ones place. If the digits are reversed the new number will be 36 less than the original number. Find the number.

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Answers

Answered by aarukvin
1

Answer:

The answer is 62.

Step-by-step explanation:

let the digit in the one's place be x

Then, the digit in the tens place = 3x

The no. formed is = 10 x 3x + x= 31x

If the digits are reversed, the new number formed is 10 X x + 3x = 13x

13x = 31x - 36

x = 2

The original no. = 31 X 2 = 62.

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