Math, asked by sarkartanisha, 7 months ago

The digit in the ten's place of a two digit number is three times of that in the one's place. If the digits are reversed, the new number will be 36 less than the original number. find the number.​

Answers

Answered by MʏSᴛᴇʀɪᴏSᴛᴀʀᴋ
2

Answer:

Originally Answered: The digit in the tens' place of a two digit number is three times that in the ones' place. If the digits are reversed, the new number will be 36 less than the original number. What is the number? Now all we have to is insert 2, and we get that the number is 10*(3*2) + 2, which would be 62.

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Answered by pranayaadhikari29
1

Answer: 62

Step-by-step explanation:

the no. should be more than 36 and less than 99 for the rule 2nd to be followed. let's assume the units place to be 'x' so the tens place will be '3x'. if we put 1 as x then the no. will be 31, that is less than 36, if we take 2 as x then the no. will be 62. if we take 3 as x the no. will be 93 ( when reversed then the new no. is not 36 less the original no.)  and at last 4 is taken as x but then the no. doesn't remain as a 2 digit no.    SO THE ANS IS 62 ( when reversed the new no. is 36 less than the original no. and also the tens place is three times of that in the on's place )  

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